Free: Contests & Raffles.
"I am really uncertain how best to go about cumulative probabilities with putting in for 4 moose hunts...it is definitely in your interest to do so"Here's how. First, compute the odds of not drawing any of the four.The odds of not drawing the first choice is 1 - 'odds of drawing'. For sake of discussion, let's assume all four units have a 1 in 100 chance. That means the chance of not drawing the first choice = 1 - .01 = .99. The odds of not drawing the second choice is .99. Same for the third and four.Therefore the odds of not drawing any of the four is .99 x .99 x .99 x .99 = approximately .9606. The odds of drawing one of them is thus 1 - .9606 or about .0394. Some people mistakenly believe that you can add individual probabilites. It's easy to see the falacity of this if you consider a coin flip. The odds of flipping heads is 50%. However, flipping the coin twice does not produce a 100% chance of getting heads.Using the reverse method is often the easiest way to solve this problem.
Quote from: WAcoueshunter on January 21, 2014, 10:36:12 AMQuote from: Bob33 on January 20, 2014, 01:40:48 PMWith maximum points (19) the odds of drawing a 49 Degree North tag are currently about 1 in 125. I think the best advice is to apply for as many units as possible (currently four) each year. If drawn in any unit, you will find quality moose.Definitely good advice, although I'm not sure about the math. In 2012, there were 13,068 49DN applicants with an average of 6 points, or 470,448 total numbers in the draw. Divide by 21 49DN tags, equals 22,402 numbers in the draw per tag. Someone with 19 points would have 361 numbers in the draw. 22,402/361 = 62, or 1:62 odds.If that same person put in for three other units, his/her overall odds would get down to 1:15 or so.Average points don't work for this. You need to compute "names in the hat" individually. There were 890,434 names in the hat for 49 DN. See below. Example - for the three applicants with 19 points, there were 1083 names in the hat: 19^2 x 3.Points Applications Names19 3 108318 5 162017 332 9594816 189 4838415 203 4567514 568 11132813 568 9599212 584 8409611 617 7465710 677 677009 847 686078 860 550407 875 428756 992 357125 1095 273754 1130 180803 1148 103322 1185 47401 1190 1190Totals 13068 890434
Quote from: Bob33 on January 20, 2014, 01:40:48 PMWith maximum points (19) the odds of drawing a 49 Degree North tag are currently about 1 in 125. I think the best advice is to apply for as many units as possible (currently four) each year. If drawn in any unit, you will find quality moose.Definitely good advice, although I'm not sure about the math. In 2012, there were 13,068 49DN applicants with an average of 6 points, or 470,448 total numbers in the draw. Divide by 21 49DN tags, equals 22,402 numbers in the draw per tag. Someone with 19 points would have 361 numbers in the draw. 22,402/361 = 62, or 1:62 odds.If that same person put in for three other units, his/her overall odds would get down to 1:15 or so.
With maximum points (19) the odds of drawing a 49 Degree North tag are currently about 1 in 125. I think the best advice is to apply for as many units as possible (currently four) each year. If drawn in any unit, you will find quality moose.
oh come on, somebody with one point cant draw and we all know it.
so the only species they don't square points for is the sheep?
First choice 49, second choice Huckleberry, third choice Aladdin, fourth choice Selkirk.
I missed this one and he's still there.... mt Spokane South
Quote from: deaner on January 21, 2014, 09:13:37 PMoh come on, somebody with one point cant draw and we all know it.sorry to be the buzz kill but back in 2006 I drew the 49 degrees north tag with only one point....saw 5 moose the opening day and shot a bull that was chasing a cow that evening.....wasn't a monster but the spread was 43 1/2"......it can be done